Quadratic formulas

Question

4t²=8t-3

Answer 1

Hey Candy

you have 4t^2=8t-3

subtract 8t from both sides

4t^2  = 8t-3

-8t       -8t

============

4t^2-8t=-3

now add 3 to both sides

4t^2-8t = -3

+3          +3

==========

4t^2-8t+3=0

from this stage on of the equation there are multiple ways of doing quadratic equations

-factoring

-completing the square

-quadratic formula

I will use factoring

4t^2-8t+3=0

(2t-1)(2t-3)=0

2t-1=0 or 2t-3=0

t=1/2 or t=3/2

Done!

Answer 2

Subtract 8t from both sides:

 

4t² - 8t = -3

 

Add 3 to both sides:

 

4t² - 8t + 3 = 0

 

Factor the quadratic

 

4t² - 8t + 3 = (2t - 1)(2t - 3)

 

So

 

(2t - 1)(2t - 3) = 0

 

2t - 1 = 0 or 2t - 3 = 0

 

2t = 1 or 2t = 3

 

t = 1/2 or t = 3/2.......Answer