
Randall K. answered 07/05/16
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Expert Chemistry Tutor
Hello Vivian,
The integrated rate equation for a second order reaction is
1/[A]t-1/[A]o=kt, where [A]t = concentration after time (t), [A]o = initial concentration, k = rate constant, & t = time (s)
What you have here is a plug and chug. Let's rewrite the equation solving for the concentration of A after 5.00 minutes (like the problem asks). Then convert 5.00 min. to s.
1/[A]t=kt + 1/[A]o
1/[A]t=(0.150 M^−1s^−1)(300 s) + 1/0.250 M = 0.0204 M => choice c
All the best,
Randall