
Bryan P. answered 06/20/16
Tutor
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Math, Science & Test Prep
You'll have to use your normal distribution tables to find the probability for any one student to score 650 or above.
First find the z score:
z = (650 - 500) / 100 = 1.5
In other words, scores of 650 or above are at least 1.5 standard deviations above the mean.
Now look at the table for z = 1.5. The heading of the table should tell you whether the values are for the area left of the z score or the area right of the z score. Some books will give you both tables. What you want to know is the area above, or to the right of z = 1.5.
The total area under the curve is always 1.0. So if your table is only giving you the side you don't want, subtract it from 1 to get the number you do want. I'm looking at a table that gives me 0.93319 for the area left of z = 1.5. So that tells me that my answer is:
P(one scored 650 or greater): 1 - .93319 = .06681
Now we must calculate it for 2, 3 4, and so on, and add them together.
P(two scored ≥ 650) = (.06681)2 = .00446
P(three scored ≥ 650) = (.06681)3 = .00029
and so on......
P(ten scored ≥ 650) = (.06681)10 = 1.77 x 10-12
∑ = .07159