Arturo O. answered • 06/16/16

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The 3 swim distances are mutually perpendicular, and therefore can be treated as the components of a displacement vector in Cartesian coordinates. Then the net distance is the magnitude of the displacement vector:

**d**= (30

**i**- 120

**j**+ 40

**k**) m

d = sqrt[(30)^2 + (-120)^2 + (40)^2] m = 130 m

Arturo O.

The diver swam east, down, and south. Those are mutually perpendicular directions.

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04/29/18

Arturo O.

By the way, I should have used -120 instead of 120 for the 'down" part of the swim, but the final answer is the same, since the quantity is squared. I edited the solution.

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04/29/18

Tejas P.

is this question jee main level ?
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05/09/21

Meera M.

04/28/18