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a girl rows a boat 6 miles upstream in 3 hours. she returns 6 miles downstream in 2 hours. how fast does she go each way?

I think the answer is 2 mph in still water and 3mph in the current

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Kevin F. | Computer Programming and Mathematics TutorComputer Programming and Mathematics Tut...
5.0 5.0 (3 lesson ratings) (3)
1
a girl rows a boat 6 miles upstream in 3 hours. she returns 6 miles downstream in 2 hours. how fast does she go each way?
 
Upstream speed is:
 
6 miles
--------
3 hours
 
Dividing numerator and denominator by 3:
 
2 miles
--------
1 hour
 
That's 2 mi/hr.
 
Downstream speed is:
 
6 miles
--------
2 hours
 
Dividing numerator and denominator by 2:
 
3 miles
--------
1 hour
 
That's 3 mi/hr.

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Ricky M. | Licensed Engineer, Math, Physics, and Computer SkillsLicensed Engineer, Math, Physics, and Co...
1
Based on the information you provided. 
 
Velocity = distance / time
 
Upstream
 
Velocity = 6 miles / 3 hours = 2 miles / hour
 
Downstream
 
Velocity = 6 miles / 2 hours = 3 miles / hour
 
 
Average velocity = 2.5 miles / hour

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Ralph L. | Algebra I, II, Visual Basic, Beginning C++ tutorAlgebra I, II, Visual Basic, Beginning C...
4.0 4.0 (1 lesson ratings) (1)
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let x be the speed of the current downstream.
let y be the speed of rowing.
 
3 (y - x) = 6      --------> (y - x) = 2 -------> y = x + 2   eq. 1        
 
2( y + x) = 6      eq. 2
 
substitute  eq. 1 to eq. 2:
 
2((x + 2) + x) = 6
 
2(2x + 2) = 6
 
2x + 2 = 3 -------------->  2x = 3 - 2 ------------->   2x = 1 ------> x = 1/2
 
substiture x into eq. 1:
 
y = 1/2 + 2      -------> y = 5/2
 
 
 
upstream:    5/2 - 1/2 = 4/2 = 2 miles/hour
downstream: 5/2 + 1/2 = 6/2 = 3 miles/hour
 
 
Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
3.0 3.0 (1 lesson ratings) (1)
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Hi Kelli;
upstream...6 miles, 3 hours, 2 mph
downstream...6 miles, 2 hours, 3 mph
 
downstream...(still-water-speed)+(current)=3 mph
upstream...(still-water-speed)-(current)=2 mph
Let's add the two equations together...
2(still-water-speed)=5 mph
still-water-speed=2.5 mph
Let's subtract the second equation from the first...
2(current)=1 mph
current=1/2 mph
Let's check our results...
upstream...
distance=(rate)(time)
6 m=[(2.5 mph)-(1/2 mph)][3 h]
6 m=(2 mph)(3 h)
The unit of hours is in the numerator and denominator of the right side of the equation.  It cancels...
6 m=(2 m)(3)
6m=6m
 
downstream...
distance=(rate)(time)
6 m=[(2.5 mph)+(1/2 mph)][2 h]
6 m=(3 mph)(2 h)
6 m=(3 m)(2)
6=6