
Andrew M. answered 06/12/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Letting c = speed of the current:
Upstream is against the current so speed upstream is 15 - c
Downstream is with the current so speed downstream is 15+c
If he travels h hours upstream, then he travels 10-h hours back downstream
Distance formula: distance = rate*time ... d= rt
27 = (15-c)h equation 1
27 = (15+c)(10-h) equation 2
(15-c)h = (15+c)(10-h)
15h - ch = 150 - 15h + 10c - ch
15h = 150 - 15h + 10c
30h = 150 + 10c
10c = 30h - 150
c = 3h - 15
27 = (15-c)h from equation 1
27 = (15-(3h-15))h
27 = (15-3h +15)h
27 = (30-3h)h
27 = 30h - 3h2
3h2 - 30h + 27 = 0
h2 - 10h + 9 = 0
(h-9)(h-1) = 0
h = 9 hours upstream
10 - h = 1 hour downstream
he travels 9 hours upstream and 1 hour downstream
c = 3h-15 so:
c = 3(9)-15 = 27-15 = 12 mph