
Patrick B. answered 06/12/20
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The lithium is 6.94 grams per mole and the Flourine is 18.998 for a total of 25.938 grams per mole...
So for every 100 grams of the aqueous solution, 39.4 grams are Lithium Flouride...
25.938 grams per mole / 39.4 grams = 0.658324873096.... moles