Hilton T. answered 05/30/16
Tutor
5.0
(198)
Former university lecturer with over 12 years experience
Fe3+ +I- = Fe2+ + I2
Assign oxidation numbers to each.
+3 -1 +2 0
Clearly, it can be seen that Fe3+ is reduced while I- is oxidized.
Write the oxidation half reaction and balance.
2I- → I2 + 2e-
Write the reduction half reaction and balance.
Fe3+ + e- → Fe2+
The number of electrons in both must be the same. This means that we must multiply the second equation by 2 to achieve this. i.e.
2Fe3+ + 2e- → 2Fe2+
Add the two balanced half reactions in which the number of electrons are the same.
2Fe3+ + 2e- + 2I- → 2Fe2+ + I2 + 2e-
Cross out the number of electrons on both sides.
2Fe3+ + 2I- → 2Fe2+ + I2
I leave the last part for you to do. What is the sum of the coefficients?