Mark O. answered 05/29/16
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Hi Amey,
x = vt
where x is the distanced, v is the speed and t is the time. We can solve for time to get
t = x/y
v2/v1 = 3/4, so v2 = (3/4)v1
v3/v1 = 5/4, v3 = (5/4)v1
t1 = x/v1
t2 = x/v2 = x/[(3/4)v1] = (4/3)x/v1 = (4/3)t1
t3 = x/v3 = x/[(5/4)v1] = (4/5)x/v1 = (4/5)t1
So, I get the time ratios to be 1 : 4/3 : 4/5
If you don't like fractions, you can multiple by the common denominator 15 and write: 15: 20 : 12
Is this what you are asking?