a linear spring is used in a physics lab. What's the slop of time verse mass?

Question

A linear spring of spring constant K is used in a lab experiment. A block of mass m is attached to the spring and the resulting period T of the simple harmonic oscillations is measured. Blocks of various masses are used in different trials, and in each case the corresponding period is measured and recorded. If T^2 is plotted versus mass the graph will be straight with what slope

Answer 1

omega = 2*pi/T = sqrt(K/m)

 

T = 2*pi*sqrt(m/K)

 

T^2 = (4*pi^2 / K) m

 

The slope of T^2 vs. m is (4*pi^2 / K).