Catherine B. answered 05/26/16
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Hi Carolina!
There are a number of ways to solve this problem, but I think the most straight forward is to first write two equations. Let's let x be the first number and y be the second number. A lot of times, I find that students have trouble translating English into Math, so I tell them translate one word at a time just like they would translate a sentence into French. The first sentence says "One number" ... that means x ... "is" ... that means equals ... "7 times" ... that means 7 multiplied by ... "another" ... that means y. So, the first sentence produces the equation: x=7y . The second sentence produces the equation 1/x + 1/y = 48/7. Now, you have two equations with two unknowns. You can solve this!! Although there are lots of paths up the mountain, so to speak, I think the easiest is to use the first equation to substitute into the second equation. (Since we know from the first equation that x=7y, we can plug in 7y for x in the second equation.) That gives us 1/(7y) + 1/y = 48/7. We need to get a common denominator to add the two fractions, so multiply 1/y by 7/7. Now we have 1/(7y) + 7/(7y) = 48/7. Add the two fractions to get 8/(7y) = 48/7. Now you can cross-multiply and solve to get y. You should get y=1/6. You can substitute back in to either equation to get x, so I'd recommend the first one ... it's simpler! You should get x=7/6. Now substitute both x and y values into the second equation to check that it works. :-)
Carolina A.
05/26/16