
Arturo O. answered 06/02/16
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Did you mean 45 minutes in addition to 1 hour? If so, then
D = (x+20)(y - 1 - 45/60) is correct, which is what you got.
Then set:
(x+10)(y-1) = (x+20)(y - 1 - 45/60)
I think your mistake was with the parenthesis in your very last equation.

Arturo O.
Before speeding up, the car covers distance D in time y traveling at speed x:
D = xy
When it increased speed by 10 km/hr it covered the same distance in a time that is 1 hour shorter, so for this trip the speed is x+10, the time is y-1, but the distance is still speed*time:
D = (x+10)(y-1)
Finally, if you add another 10 km/hr to speed, the time is reduced further by 45/60 of a hour:
D = (x+20)(y-1-45/60)
All of the D's are the same, so
(x+10)(y-1) = (x+20)(y-1-45/60)
For this last equation you have:
D = x+10(y-1)=x+20(y-1)-45/60
(x+10) must multiply all of (y-1), and (x+20) must multiply all of (y-1-45/60). That is what I meant by the parentheses.
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06/05/16
Amey B.
06/05/16