Amey B.

asked • 05/21/16

time speed distance

a car travels from p to q at a constant speed if its speed were increased by 10 kmhr it would have taken one hour lesser to cover the distance it would have taken further 45 lesser if the speed was further increased by 10 kmh what is the distance between the two cities
 
x=speed
y=time
D    =      S          *    T
             x+10      *    y-1  (why i put one because it is in hour) 
             x+20      *   (y-1)-45/60
 
now Distance is same
 
x+10(y-1)=x+20(y-1)-45/60 
 
is this equation is right if wrong where i did wrong please explain dont figure out different way i want to find out my mistake.

1 Expert Answer

By:

Arturo O. answered • 06/02/16

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Amey B.

but why parenthesis explain me
because in second time he increase his speed so the time he consume is 45 min less so what ever we give for first time that is y-1 that minus 45/60
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06/05/16

Arturo O.

Before speeding up, the car covers distance D in time y traveling at speed x:
 
D = xy
 
When it increased speed by 10 km/hr it covered the same distance in a time that is 1 hour shorter, so for this trip the speed is x+10, the time is y-1, but the distance is still speed*time:
 
D = (x+10)(y-1)
 
Finally, if you add another 10 km/hr to speed, the time is reduced further by 45/60 of a hour:
 
D = (x+20)(y-1-45/60)
 
All of the D's are the same, so 
 
(x+10)(y-1) = (x+20)(y-1-45/60)
 
For this last equation you have:
 
D = x+10(y-1)=x+20(y-1)-45/60
 
(x+10) must multiply all of (y-1), and (x+20) must multiply all of (y-1-45/60).  That is what I meant by the parentheses.
 
 
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06/05/16

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