An 85-g sample of iron is at an initial temperature of 38 °C. If 529 cal of heat are applied to the sample, what is the final temperature of the iron?

Question

do it with step please?

Answer 1

First you need to realize that this a calorimetry problem where you heat a sample of iron in a calorimeter. In all these problems you use the following formula.

 

q = s x m x delta T

 

In this formula q is the heat either released or taken, m is the mass of the sample, s is the specific heat capacity (a measure that states how much heat is required to raise 1 g of a sample by 1^oC) and deltaT = T_final - T_inital. 

 

In this question

 

q is a positive quantity since 529 cal of heat is applied to the sample, therefore q = 529

m = 85 g

T_initial = 38^oC

T_final is unknown

s is the specific heat capacity of iron, which should be given in the problem.

 

Solving for T_final

 

q = sm(T_final - T_initial)

T_final = (q/sm) + T_initial

 

Plugging all the known values that you're given into the formula above should help you find the final temperature of iron.