Jada M.

asked • 05/19/16

Divide the number 64 into two parts so that one part shall be seven times the other.

I need this answered ASAP!!!!!!!!

Andrew M.

The question here is whether "divide the number 64 into two parts" means to divide it into two numbers whose product is 64 ... or divide it into two numbers whose sum is 64.  My answer is based on the belief that we were looking for factors as opposed to sums.
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05/19/16

Larry N.

Your equations are:
x+y=64
x=7y
To solve you use substitution:
(7y)+y=64
Then you solve for x and y:
(7y)+y=64
8y=64
/8  /8
y=8
 
x=7y
x=7(8)
x=56
 
 
 
Sorry, I couldn't put this in the answer spot, but I don't have an account and I could only sign up as a student and I was not able to find this question and I don't know if I could even answer this with a student account.
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05/19/16

Andrew M.

Larry,
My comment was basically merely stating that Jada's original
question was unclear in it's meaning.  I have no problem doing
the system of equations, which was also done by Philip P. and
Carl M.  However, if Jada's intention was that the equations were
meant to relate to two numbers whose product is 64 then the
numbers in question are x, 7x and the equation is:  x(7x)=64.
Thanks.
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05/20/16

3 Answers By Expert Tutors

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Andrew M. answered • 05/19/16

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Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

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Factors of 64 such that one is seven times the other:
 
x(7x) = 64
7x2 = 64
x2 = 64/7
take square root of both sides
x = ±√(64/7)
= ± √64/√7
= ±8/√7
 
7x = ±8√7
 
your numbers are:
8/√7 and 8√7
or
-8/√7 and -8√7
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Carl M. answered • 05/19/16

Tutor
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Pre-Algebra, Algebra 1, Algebra 2 and Geometry Tutoring

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Let x equal one part and y = 7x equal the other part. Therefore,
  • x + y = 64, substitute the value of y.
  • x + (7x) = 64
  • 8x = 64
  • x = 64/8 = 8. Solve for y.
  • y = 7x = 7(8) = 56.
So x = 8 and y = 56. To check go back to original equation and substitute these values.
  • x + y = 64
  • 8 + 56 = 64
  • 64 = 64   Checks!
 
 
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