The perimeter of a rectangular floor is 180 feet. Find the dimensions of the floor if the length is five times the width

Question

The perimeter of a rectangular floor is 180 feet . Find the dimensions of the floor if the length is five times the width.

 

The floor has a length of ?feet and a width of ? feet.

Answer 1

Perimeter 180 feet

 

Let w be the width, so length is 5w.

 

so,

 

2w + 2(5w) = 180 

 

2w + 10w = 180

 

12w = 180

 

w = 15, so length is 75

 

Answer 2

Hi again Kevin;

length...5x

width...x

Perimeter=2(length + width)

180=2(5x+x)

180=2(6x)

180=12x

Let's divide both sides by 12...

180/12=(12x)/12

15=x

width...15 feet

length...5(15)=75 feet

 

Let's check our work...

180=2(75+15)

180=2(90)

180=180

Answer 3

Hey Kevin -- cutting the perimeter in half means one L and one W is 90ft ...

 

since the ratio is 5:1, W is 1/6 of 90ft or 15ft ... 75L, 15W does it ... Regards :)

Answer 4

DEFINITION:    2*W + 2*L = PERIMETER OF A RECTANGLE,  W= WIDTH, L= LENGTH

 

GIVEN:  L= 5*W

 

2*W + 2*(5*W) = 180

 

2*W + 10*W = 180

 

12 * W = 180

 

W= 180 / 12

 

W=  15

 

 

L=5*W

 

L = 5*15

 

L = 75

******************

 

CHECK:  2*W + 2*L = 180  

 

2*15 + 2*75 = ?

 

30 + 150 = 180   OK!