Hilton T. answered 05/05/16
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Former university lecturer with over 12 years experience
a. KE = 1/2 mv2 ∝ T
∴ v2 ∝ T
v22/v12 = T2/T1
T2 = v22/v12 T1 = (v2/v1)2. T1
b. Use Gay Lussac's Law. P2/T2 = P1/T1
c. F = P2 x Area of a wall (assume a cube of side 1 m)