Joshua Psalms T. answered 05/03/16
Tutor
5
(5)
Civil EIT, Former College Professor of Mathematics (in Asia)
I don't know if this is the one you're looking for but there is formula:
P(x) = nCx * px * qn-x
P(x) = probability that x successes will occur in n trials
n = no. of trials
x = no. of successes (that you want)
C = number of combination
p = the probability of a success in each trial
q = the probability of a failure in each trial
You have 4 pennies to toss so you have 4 trials.
You want 4 pennies to be all heads (in this problem, heads = success) so you also have 4 successes.
Lastly, how many ways will there be 4 heads in 4 toss coins, obviously there's only 1 or mathematically (4C4 = 1).
The probability of a head (success) in each toss coin is of course, 1/2. The same as the probability of failure (tails).
Inserting everything:
P = 4C4 * (1/2)4 * (1/2)0
P = 1/16