One diagonal of a kite is four times as long as the other diagonal. If the area of the kite is 72 square meters, what are the length s of the diagonals?

Question

I am not sure how to do this because if you plug in 72 for area then you are left with 2 variables.

Answer 1

the area of a rhombus is 1/2 times the product of the two diagonals

A=(1/2)(d1)(d2)

72=(1/2)(n)(4n)

72=(1/2)(4n^2)

72=2n^2

36=n^2

n=6 meters

4n=24 meters