Chemistry Gas Laws

Question

1. An unbreakable meteorological balloon is released from the ground.Ground level pressure is 98.5 KPa and the temperature is 18.0 Celsius. The balloon contains 74.0 liters of Hydrogen gas. As the balloon soars up, the pressure drops to 27.0 KPa. What is the new volume of the balloon, assuming no temperature change?

2. Re-read question 1, but considering in the real world when you go up in altitude the temperature does change. what is the actual volume of the meteorological balloon if the temp also drops 79.0 celsius from its original temperature? 

Answer 1

1. since there is no temperature change, use Boyle's law

P₁V₁ =P₂V₂           or  V₂ = P₁V₁/P₂

 

2. Since volume, temperature and pressure all change, use the Combined Gas equation 

P₁V₁/T₁ = P₂V₂/T₂    or  V₂ = P₁V₁T₂/(T₁P₂)

 

Substitute the values. Remember to use the Kelvin Temperature, not degrees Celsius.