During one season, a basketball player made 353 of 765 free throws. At that rate, how many free throws would the player make in another 600 attempts?

Question

Need this within the next hour, please!

Answer 1

Based on the fact that the player made 353 out of 765 free throw attempts, we can figure out exactly what the player's success rate is.  Divide 353 by 765:

 

353/765 = .461 = 46.1%

 

So this player makes 46.1% of all his free throw attempts.  Now, what's 46.1% of 600?  Multiply it out:

 

.461 * 600 = 276.6 = 277 (round up, since you can't make part of a free throw)

 

So the player would make approximately 277 out of his next 600 free throw attempts.

 

I hope this helps!