In mL, how much of 3Cu(PO4)2 and 2Na3PO4 will I need to make 10 grams of Cu3(PO4)2?

Question

Balanced equation: 2Na3PO4(ac) + 3Cu(NO3)2(ac) = Cu3(PO4)2(s) + 6NaNO3(ac)

 

Na3PO4 molarity: (1.0 M)

Cu(NO3)2: (5.0 M)

 

I don't know how to calculate how much of 2Na3PO4(ac) and 3Cu(NO3)2(ac) is required (in mL) to make 10 grams of Cu3(PO4)2.

Answer 1

In mL, how much of 3Cu(NO₃)₂ and 2Na₃PO₄ will I need to make 10 grams of Cu3(PO4)2?
Balanced equation: 2Na₃PO₄(ac) + 3Cu(NO₃)₂(ac) = Cu₃(PO₄)₂(s) + 6NaNO₃(ac)

Na₃PO₄ molarity: (1.0 M)
Cu(NO₃)₂: (5.0 M)

 

 

STEP 1. , Find the molar mass of the following (use a Periodic Table):

 

Cu₃(PO₄)₂ =3(63.55) + 2(31 +64) = 380.65

 

STEP 2.  Change the grams to moles.

moles = grams/ molar mass

 

10 g Cu₃(PO₄)₂ = 10/380.65 = 0.0263 mol

 

STEP 3. Use the mole ratios.

By the mole ratios (look at the coefficients from the equation), it requires 3 moles Cu(NO₃)₂ and 2 moles Na₃PO₄ to form 1 mole of Cu₃(PO₄)₂

This means that to produce 0.0263 mole Cu₃(PO₄)₂, 

3 x 0.0263 = 0.0789 mole Cu(NO₃)₂ and

2 x 0.0263 = 0.0526 mol Na₃PO₄ are required.

 

STEP 4. Use the Molarity formula to find the volume.

Molarity = moles/ Liters

or Liters = moles/ Molarity

Volume of Cu(NO₃)₂ = 0.0789 mol/ 5.0 M = 0.01578 L ≈ 16 mL

Volume of Na₃PO₄ = 0.0526 mol/ 1.0 M = 0.0526 L ≈ 53 mL

 

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Answer 2

I see you have the molarity for the two solutions but you would need a bit more information like the starting mass from one of the products or liters of solution.