Morgan D.

asked • 04/22/16

Simplifying a function to get a tangent line

In the middle of solving this implicit function/using implicit differentation to find its tangent line, this is what I have so far:
Original function: y^3+x^3-2xy=8 (find tangent line at (2,2))
I started the implicit differentation to find y' and got: (3y^2)(y')+3x^2-2xy'+2y=0
I know I need to factor out the y' and get it on the LHS but I'm having trouble getting beyond this point correctly...not sure if it's a simple algebraic issue or what.
Thank you!

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