
John M. answered 04/19/16
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Certified Math Teacher with Statistics Masters
This problem describes a system of linear equations because it has two unknowns (room cost and meal cost) which will become our variables x and y. Let x = room cost and y = meal cost.
A banquet for 50 people would be 50 meals at $y each plus the cost of the room at $x. Therefore:
x + 50y = 800
A banquet for 100 people would be 100 meals at $y each plus the cost of the room at $x. Therefore:
x + 100y = 1250.
If you solve both equations for x:
x = 800 - 50y and x = 1250 - 100y
You can now set the equations equal since they both equal the same amount, x, then solve for y.
800 - 50y = 1250 - 100y
800 = 1250 - 50y
-450 = -50y
9 = y
Each meal costs $9. Using one of the solved for x equations, you can plug y in to find the value of x.
x = 800 - 50(9) = 800 - 450 = 350
The room costs $350.
Now you have all the information you need to answer to two parts:
A) 350 + 200(9) = 350 + 1800 = $2150
B) 350 + 9y = 2330
9y = 1980
y = 220
220 people could attend.