f(x) = √(3-√x)
We can't take square roots of negative numbers (if x is real) so x≥0 (so that √x is real) and 3-√x ≥ 0 (so that √(3-√x) is real).
Thus, x ≥ 0 and -√x ≥ -3
x ≥ 0 and √x ≤ 3
x ≥ 0 and 0 ≤ x ≤ 9
Domain: [0, 9]