Don L. answered 04/10/16
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Amey, the question is misleading. If x is the total distance traveled and he traveled 3/5 of the distance by rail, that leaves only 2/5 of the remaining distance traveled by bus and includes the 6.5 kilometers he walked.
The equation looks like this:
Total distance traveled - distance traveled by rail - distance traveled by bus - distance walked = 0
x (total distance) - 3/5 * x (distance by rail) - 17/20 * 2/5 * x (distance by bus) - 6.5 (distance walked) = 0
This becomes:
x - 3/5 * x - 34/100 * x - 6.5 = 0
x - 60/100 * x - 34/100 * x = 6.5
x - 94/100 * x = 6.5
6/100 * x = 6.5
Multiply both sides by 100
6x = 650
Divide both sides by 6
x = 108.33
Total distance traveled is 108.33 kilometers.
Check
3/5 or .6 times 108.33 ≈ 65 kilometers traveled by rail.
That leaves 43.33 kilometers traveled by bus and on foot.
17/20 or .85 times 43.33 = 36.85 kilometers traveled by bus.
That leaves 6.5 kilometers traveled on foot.
65 (by rail) + 36.85 (by bus) + 6.5 (on foot) = 108.33
Questions?
Amey B.
04/14/16