For the following reaction, 3.29 grams of potassium hydroxide are mixed with excess carbon dioxide. The reaction yields 3.69 grams of potassium carbonate.

Question

For the following reaction, 3.29 grams of potassium hydroxide are mixed with excess carbon dioxide. The reaction yields 3.69 grams of potassium carbonate.

 

What is the theoretical yield of potassium carbonate ? grams

What is the percent yield of potassium carbonate ? %

Answer 1

2KOH+CO2--> K2CO3+H20

 Mole KOH= 3.29 :( 39+16+1) = 0.0588 mol. Mole of K2CO3= 1/2 mole of KOH= 1/2 x 0.0588= 0.0294 mol.

Grams K2CO3 product form: mass= mole x Molar Mass= 0.0294x(39x2+12+16x3)= 4.0572 g--> theoretical yield of K2CO3. 

% yield od K2CO3= (reaction yield)/ theoretical yieldx100= 3.69:4.0572x100=90.9%