
Kenneth S. answered 04/03/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
E = IR relates voltage (E volts), current (I amperes) and resistance (R ohms). [Your first sentence erroneously says 'current R'.]
E = 60•258 is given, and this will be held constant. Then this same E = I•150.
Setting these two E values equal, we have 60•258 = I•150.
You can solve for I now.