Acceleration

Question

An object has a constant acceleration of 40 ft/sec², an initial velocity of -20 ft/sec, and an initial position of 10 ft. Find the position function, s(t), describing the motion of the object.

Answer 1

s(t) = (1/2)at² + v₀t + s₀  where:

• s(t) = the object's position at time t
• a = the object's acceleration = 40 ft/s²
• v₀ = the object's initial velocity = -20 ft/s
• s₀ = the object's initial position = 10 ft

 

s(t) = (1/2)(40)t² + (-20)t + 10 = 20t² - 20t + 10