Help with quadratic equation

Question

Hi, I keep getting wrong answer to this : √2x² — 3x + √2 =0 

Answer 1

(√2x - 1)(x - √2) = 0

 

√2x - 1 = 0

      √2x = 1

           x = 1√2 = √2/2

 

x - √2 = 0

         x = √2

Answer 2

 √2x² - 3x + √2 = 0

 

By the quadratic formula, x = (3 ± √[(-3)²-4(√2)(√2)])/(2√2)

 

                                       = (3 ± √1)/(2√2)

 

                                       = 4/(2√2) or 2/(2√2)

 

                                       = 2/√2, 1/√2

 

                                       = √2, √2/2