Claudia C.

# How do I find perimeter of the figure with the given vertices? Confused here!

D(0,1),E(5,4) and F(2,6)

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Claudia C.

I need to see DF calculation. Should be same as DE. I'm off .5. I should be getting 34, 13, 34. I'm getting 34, 13, 29. Not sure what I did wrong.
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03/03/16

Marina B.

If you have the points correctly, then I also got square root of 29 for DF:
D(0,1) and F(2,6)
d = √[(x2 - x1)2 + (y2 - y1)2]
d = √[(2 - 0)2 + (6 - 1)2] = √[(2)2 + (5)2] = √[4+ 25] = √[29]
Does the back of the book say it's √[34]?
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03/03/16

Claudia C.

No two people answered my questioned and other person said it was an isosceles triangle, but I must have done it right and he did it wrong. Thank you so much for verifying for me.
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03/03/16

Marina B.

Okay, Claudia, small mistakes happen to everyone ;) especially if we try to do it in our heads. You are welcome.
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03/03/16

Alan G.

Thanks for the clarification. I was mistaken about the triangle being isosceles. Marina is correct about the side DF being equal to √29. My fault was (as she said) that I did this in my head and was tired at the time.
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03/03/16

Marina B.

I guess the lesson here is (and it's a very good lesson) in a test situation write down all your steps/work. It will be easier to track down any mistakes later. Otherwise, you can lose points for human error. The other being, have confidence in your work if you see you have followed the "recipe" of the formula correctly.
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03/03/16

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