Nancy and Kerri have the same amount of coins. Nancy has only dimes and Kerri has only quarters.

Question

if Kerri has $3.00 more than Nancy, how many coins does each girl have?

Answer 1

Let d = # of dimes Nancy has and let q = # of quarters Kerri has

 

d = q

 

.1d + 3.00 = .25 q

 

Substitute q for d since they are equal and solve for q

 

.1(q) + 3.00 = .25q

3.00 = .25q - .1q

3.00 = .15q

q = 3.00 / .15 = 20

 

d = q = 20

 

So each girl has 20 coins