
Mark M. answered 01/29/16
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Mathematics Teacher - NCLB Highly Qualified
s represents the speed of the slower
s + 3 represents the speed of the faster
d = r · t
2s represents the distance of the slower
2(s + 3) represents the distance of the faster
2s + 2(s + 3) = 210
2s + 2s + 6 = 210
4s + 6 = 210
4s = 204
s = 51
The slower truck moves at 51 mpg and the faster at 54 mph.