
Chris C. answered 01/28/16
Tutor
New to Wyzant
Recent Mathematical Sciences Grad
Let S be the third side. Notice that the second side is 2S-1. Then from the triangle inequality we get our system.
side 2 + side 3 > side 1
2S -1 + S > 17 (Move the 1 and combine the S's)
3S >18 (Divide both sides by 3)
S > 6
This gives us a lower bound for S
side 1 + side 3 > side 2
17 + S > 2S - 1 (Move the 1 and the S)
17 + 1 > 2S - S (Combine like terms)
18> S
Now we have an upper bound for S
Therefore 6<S<18
There is one last detail recall, second side = 2S-1, thus to find the possible values for that side you must plug in the lower and upper bounds for S
side 2 + side 3 > side 1
2S -1 + S > 17 (Move the 1 and combine the S's)
3S >18 (Divide both sides by 3)
S > 6
This gives us a lower bound for S
side 1 + side 3 > side 2
17 + S > 2S - 1 (Move the 1 and the S)
17 + 1 > 2S - S (Combine like terms)
18> S
Now we have an upper bound for S
Therefore 6<S<18
There is one last detail recall, second side = 2S-1, thus to find the possible values for that side you must plug in the lower and upper bounds for S