Determine how many moles of particles are present in 1.0 L of the following solution? Please check my answer? Chemistry

Question

0.02 M CuSO4

 

Can you check my work?

Since CuSO4 is a m + nm, it is an ionic compound and will break up into ions in a polar? solution.

 

(0.02 mol CuSO4 / 1.0 L soln)(2 ions/1 mol CuSO4) = 0.04 M ions

 

 

Another problem to check if you have time: 0.050 M (NH4)2CO3

 

 I got 0.15 M ions

 

Thanks for the help!

Answer 1

Hi Angelica,

 

Your calculations are correct, although not quite totally complete (the numeric value is the same, however).

 

Since you are being asked for moles, and your given is 1.0 L of solution, you need to start with the 1.0 L.

 

(1.0 L solution) × (0.02 mol CuSO₄/1 L solution) × (2 mol  ions/1 mol CuSO₄) = 0.04 mol ions

 

The same holds true for your second answer.

 

If I were grading these as a test question, I'd ding you for a half point for not having the initial amount explicitly written (but I'm sometimes generous in partial credit).

 

Jim Scripko