Inactive Tutor answered 01/19/16
Tutor
New to Wyzant
Let's call the distance from Aya's house to her friends house D.
The distance back has to be the same, right? Now let's consider the times for each part. The total time is 3 hours, so the sum of the 2 legs of the trip have to total to 3.
Tout + Tback = 3
The distance there is
Vout * Tout = D
The distance back is the same, but using the 'back' time and speed.
Vback * Tback = D
Since both of these are equal to D, we can set them equal to each other
Vout * Tout = Vback * Tback
Now we look back at the time equation and solve for Tout
Tout = 3 - Tback
Plug all our given info in
16 * Tout = 80 * (3 - Tout)
16T = 240 - 80T
96T = 240
T = 240/96
T = 2.5 hours, this is the time it takes to go to Aya's friend's house.
To fin the distance, we look back and pick one of our distance equations and plug this time into it. We should pick the first one because it is a little easier.
Vout * Tout = D
16 * 2.5 = D
40 km = D
The distance between their houses is 40 km.
I hope this helps! Please ask any questions if you have them.