
Joseph S. answered 03/03/16
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All levels of physics, algebra, geometry, precal, calculus. Patient
vo = 120/3.6 = 33.33 m/s
net force = Ff =(mu)N =(mu)mg = -ma
a=(mu)g = (0.62)(9.8) = -6.076 m/s/s
v^2 =vo^2 + 2ax
0 = 33.33^2 +2(-6.076)x
x = 91.41 m
b) since the deceleration a = (mu)g, it is independent of the mass of the car. So for a massive or light car we end up with the same deceleration so it will be the same stoping distance.