find the distance . P1=(3,-3); P2=(1,4)

Question

Find the distance. P1=(3,-3);P2=(1,4)

Answer 1

Hi again Kevin;

a²+b²=c²

(x-x₁)²+(y-y₁)²=c²

  _______________

√[(x-x₁)²+(y-y₁)²]=c

   _____________

√[(3-1)²+(-3-4)²]=c

  ________

√(2)²+(7)²=c

  _____

√4+49=c

  __

√53=c

 

7.3=c

 

Answer 2

 

 

(3, -3) and (1, 4)

 

distance formula: √[ (x₂ - x₁)² + (y₂ - y₁)² ]

 

so,

 

√[(1 - 3)² + (4 -(-3))² ]

 

√[(-2)² + 7²  ]

 

√(4 + 49) = √53