Bob A. answered 11/09/13
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To find the area under a curve you need to integrate the function defining the curve.
Assuming that, by 3x2 you really mean 3x2
and not 3x2 which could be = 6x or =6 depending on if the x is a variable or the times sign.
integral f(x) dx = int(3x2 + 5x)dx
= 3 int(x2)dx + 5 int(x)dx
= 3 1/3(x3) + 5 1/2(x2)
= x3 + (5x2)/2 + Constant
We probable should really do a definite integral and remove the constant,
is there a domain defined for the function so we would kow what points to integrated between?
Andre W.
tutor
This parabola intersects the x-axis at -5/3 and 0. Evaluate the integral Robert gave you between -5/3 and 0 to get the area between the curve and the x-axis.
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11/09/13
Christopher B.
11/09/13