A jar contains Jelly-Beans, and there are 87 pink, 74 purple, 35 white, 70 black, 25 orange, and 47 green. If two Jelly-Beans are chosen from the jar, what is t

Question

I have a feeling that you should add all of the beans together and divide by 2, but I'm not sure that is correct???

 Full question: A jar contains Jelly-Beans, and there are 87 pink, 74 purple, 35 white, 70 black, 25 orange, and 47 green. If two Jelly-Beans are chosen from the jar, what is the probability that one is pink and one is purple? Round to the nearest thousandth.

Answer 1

Hi Violet,

 

There is one important fact that is not stated in the problem and that is whether the first bean is replaced before choosing the second one. If the first jelly bean is not replaced and there is a total of 338 jelly beans, then the probability of choosing a pink jelly bean is 87/338. Now there are 337 jelly beans left and the probability of choosing a purple jelly bean is 74/337. Therefore the probability of choosing a pink bean and then a purple bean is

 

                                  87 . 74

                                 338  337

The probability of choosing a pink bean and a purple bean could take place by choosing the purple one first and then the pink one which would be

                                               74 . 87

                                               338 337    Therefore the probability of choosing a pink bean and a purple bean would be calculated as

                                  87 . 74     +   74 . 87     =   .113

                                 338  337        338  337

If the first jelly bean is replaced before choosing the second, the denominators of all of the fractions would be 338 which makes little difference in the final answer, because rounding to the nearest thousandth will be exactly the same.

                                    

Answer 2

Hi Violet, the problem statement is cut off or this one as well. Please check what the rest of the second sentence is.