I'm not sure about all the question marks; if the integral is meant to be ∫3x-4dx,
you would simply build the solution around x-3 because x-3 differentiates back to
-3x(-3 − 1) or -3x(-4) or -3x-4.
This almost gives the integrand 3x-4 above. Put a negative sign to the left of x-3
and add a "C" (for some undetermined constant or exact number) to -x-3 to obtain
-x-3 + C.
Test this answer by taking the derivative of -x-3 + C: d(-x-3 + C)/dx gives
[-(-3)x(-3 − 1)] + 0 which will reduce to 3x(-4) or 3x-4, the original integrand above.