
Mario T. answered 12/02/15
Tutor
4.5
(11)
Cornell University Class of 2015 BS in Mechanical Engineering
y= (1500 - 20(t-65))t
t-65 is the amount of trees added
t is the amount of trees at any point
1500 minus 20(t-65) is how much the yield goes down for every tree added
this total times t, the amount of trees, will give us the new yield
To get the maximum, we set the derivative of the above function equal to 0.
y = 1500t - 20t2 + 1300t
y = -20t2 + 2800t
y'= -40t + 2800 --> the derivative
0 = -40t + 2800 --> set derivative equal to 0 and solve for t
40t = 2800
t = 70
This is the amount of trees that will maximize the yield.
We then plug this into the original equation to get the actual maximum yield
y max = 98000 = maximum yield