Find the product of 2n-4 and n^2+6n-4

Question

Please explain how You do it in complete sentences i need it tomorrow for exam. Thanks :)

Answer 1

Another and easier way to look at it is to think of one of the factors as the greatest common factor of the expression.  Let the factor (n²+ 6n - 4) be that greatest common factor.  So you will have

 

(n² + 6n - 4)(2n - 4) =

 

2n(n² + 6n - 4) - 4(n² + 6n - 4)

 

 

Now use distributive property to get rid of the parentheses and then combine like terms to simplify.  You will get the same product that Donna has provided.

Answer 2

(2n-4)(n^2+6n-4)

 

First you would take the 2n and multiply it by each part in the second factor.

 

(2n)(n^2) + (2n)(6n) + (2n)(-4) = 2n^3 + 12n^2 -8n

 

Second you would take the -4 and multiple it by each part of the second factor.

 

(-4)(n^2) + (-4)(6n) + (-4)(-4) = -4n^2 -24n +16

 

Finally you would take the two answers from the multiplication and add the like terms together.

 

         2n^3 + 12n^2 -  8n

                      -4n^2 -24n +16

        ________________________

       

         2n^3 + 8n^2 - 32n +16

 

 

I hope this helps.