
Bill P. answered 11/29/15
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Begin with f(x) = ax^2 + bx + c.
5 = a(1)^2 + b(1) + c implies 5 = a + b + c Equation (1)
16 = a(2)^2 + b(2) + c implies 16 = 4a + 2b + c Equation (2)
31 = a(3)^2 + b(3) + c implies 31 = 9a + 3b + c Equation (3)
This is 3 equations in 3 variables. We will solve for a,b, and c.
We can eliminate c by subtracting (1) from (2) to obtain: 3a + b = 11 Equation (4)
We can eliminate c by subtracting (1) from (3) to obtain: 5a + b = 15 Equation (5)
If we subtract (4) from (5) we get 2a = 4. Therefore, a = 2.
By substitution with 2 in place of a in (5) gives us 5(2) + b = 15 which means 10 + b = 15 which means that b = 5.
Finally, using equation (1) with a = 2, and b = 5 yields that c = -2.
Thus, f(x) = 2x^2 + 5x - 2.