A man inspects every 36th egg for cracks and every 48th egg for weight. What is the first egg he checks for both?

Here you go Brian...

Since he checks every 36th egg for cracks and every 48th egg for weight let x = a multiple of 36 and let y = a multiple of 48. for the two to happen together we know that 36x = 48y.

Then rearranging we know that x/y = 48/36. Reducing the ratio of x/y = 4/3

So (36)(4) = (48)(3) = 144. So the 1st egg checked for both would be egg 144.

## Comments