
Ajene W. answered 11/22/15
Tutor
5
(5)
U.S. Marine Engineer For Math Tutoring
x=amount invested
a=percent of A
b=percent of B
y=return after one year
rules: .75>=a>=.5 ; b=1-a
equation: y=1.13(xa)+1.10(x(1-a))
y=1.13(xa)+1.10(x-xa)
y=1.13(xa)+1.10x-1.10xa
y=1.10x+.03xa
you'll see that this creates a linear equation with a positive slope.
substitute a dollar value for x. I'll use 1.
y=1.10(1)+.03(1)(a)
y=1.10+.03a
when 'a' is between .5 and .75 the maximum value for 'y' is 1.123. This occurs when a=.75
so to sum up the answer
Optimal amount in type A 300,000*.75=225,000
Optimal amount in type B 300,000*.25=75,000
Optimal return in one year will be 300,000*1.123=336,900.