Recognize that the problem is describing the components of the
"slope-intercept" form (y=mx+b) of a linear equation. It describes...
1. "...increases 1 unit for every 5 units...decreases" describes
slope, "m" ("rise over run"). Increase is a positive value (up,
dependent value "y") and decrease is a negative value (left,
independent value "x"). So we have...
m=1/-5=-(1/5)
2. "...value of the function at 0 is 3" describes the y-intercept, "b",
or coordinate (0,3).
b=3
Let's substitute these values into the slope-intercept form of
the linear equation...
y=-(1/5)x+3......Eq1, slope-intercep form of linear
equation.
Let's check our solution by plugging in the point (0,3) from
the problem statement into Eq1...
3=-(1/5)(0)+3...substitute "0 for x" and "3 for y".
3=0+3..............simplify
3=3..................true, √check, our solution equation is correct.
Always check your solution and work!
So our solution equation rewritten in function notation reads...
h(x)=(-1/5)x+3
h(x)=(-1/5)x+3