A gas starts with a volume of 1.05 L at 60 degrees C and 3.9atm. What is the new volume if the gas is now held at 20 degrees C at 455kpa..?

Question

1 Atm: 101.3Kpa

L: Liters 

C: Celsius 

Answer 1

Hi, Morgan.

 

You'll need to be in consistent units for the calculation. 455 kPa = 4.49 atm

 

Also, your temperatures need to be absolute: degk = degc + 273.15

 

Then using the ideal gas law for different conditions:

 

P2*V2/T2 = P1*V1/T1

 

or: V2 = P1*V1*T2/(P2*T1)

 

This all assumes the pressures given are absolute instead of gauge.

 

If you need more help on this or similar problems please contact me.

 

Bob K.