
Al K. answered 11/01/15
Tutor
4.5
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25 years of teaching algebra and calculus
Let the volume of the pool V be π r2 h where h is the height, h=h(t)
V= π r2 h , Now differentiate using the chain rule
dV/dt is the water rate coming from the hose
dV/dt = (dV/dh).(dh/dt)
dh/dt is given as 0.4 in per min = 0.033 ft/min
dV/dt=(π r2). 0.033 = (3.14)(100). (0.033) = 10.36 ft3/min=(10.36).(7.48)=77.5 gal/min
V= π r2 h , Now differentiate using the chain rule
dV/dt is the water rate coming from the hose
dV/dt = (dV/dh).(dh/dt)
dh/dt is given as 0.4 in per min = 0.033 ft/min
dV/dt=(π r2). 0.033 = (3.14)(100). (0.033) = 10.36 ft3/min=(10.36).(7.48)=77.5 gal/min