Arthur D. answered 11/01/15
Tutor
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(274)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=r*t
d=34*t (freight)
d=85*(t-3) (passenger)
equate the two right sides
34t=85(t-3)
34t=85t-255
34t-85t=-255
-51t=-255
51t=255
t=255/51
t=5 hours before the passenger train caught up to the freight train