Let's see what we know, the change in height was Δy = 6.16m
the acceleration vertically = ay =-g=-9.8 m/s2
at the top of the jump, for a tiny moment final velocity vyf =0 m/s
So we can use a kinematics equation to solve for initial velocity when we know, displacement, acceleration, and final velocity. Vf2 = vi2+ 2aΔy
Substitute the known values and solve for initial vertical velocity.
This is the vertical vector we need to solve the problem. His running speed at an angle θ must equal this vertical vector.
vyi =running speed sinθ